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Mathematics Mcqs

Mathematics MCQs include a wide range of solved multiple-choice questions from basic arithmetic to advanced mathematics. These questions cover topics such as Algebra, Geometry, Trigonometry, Calculus, Probability, Statistics, and Arithmetic. They are especially designed for students and candidates preparing for PPSC, FPSC, CSS, PMS, NTS, KPPSC, SPSC, and other competitive exams. Practicing these MCQs helps improve problem-solving skills, numerical ability, and analytical reasoning, making them ideal for both academic learning and job test preparation.

Find LCM of 27 & 63:

A. 100
B. 189
C. 81
D. 216
Correct answer is: B. 189
Prime factors: 27 = 3³, 63 = 3²×7 → LCM = 3³×7 = 189.

A profit of rupees 12300 is distributed among the three partners in the ratio 4/3:7/6:11/12. Find the share of the third partner?

A. 4200
B. 3300
C. 4600
D. None of these
Correct answer is: B. 3300
? Calculating the Ratio The ratios given are 4/3, 7/6, and 11/12. To simplify, we find a common denominator, leading to the ratio 16:14:11.
? Total Profit Calculation The total profit of 12300 rupees is divided based on the total of the simplified ratio parts, which sums to 41 (16+14+11).
? Share of the Third Partner The share of the third partner, represented by the ratio part 11, is calculated as (11/41) * 12300 = 3300 rupees

A tank in the shape of a cylinder with a diameter of 2.4 m and height 6.4 m contains oil up to the brim. Find the number of complete smaller cylindrical containers, each with a base radius of 8.2 cm and height 28 cm, that can be completely filled using the oil from the tank?

A. 4895 m³
B. 92160 m³
C. 4795 m³
D. 4761 m³
Correct answer is: A. 4895 m³
Find the volume of the larger tank:
Radius of the larger tank = Diameter / 2 = 2.4 m / 2 = 1.2 m
Volume of a cylinder = π * radius² * height
Volume of the larger tank = π * (1.2 m)² * 6.4 m
Volume of the larger tank ≈ 28.94 m³
2. Find the volume of the smaller containers:
Radius of the smaller container = 8.2 cm / 100 = 0.082 m
Height of the smaller container = 28 cm / 100 = 0.28 m
Volume of a smaller container = π * (0.082 m)² * 0.28 m
Volume of a smaller container ≈ 0.00059 m³
3. Calculate the number of smaller containers:
Number of containers = Volume of larger tank / Volume of smaller container
Number of containers ≈ 28.94 m³ / 0.00059 m³
Number of containers ≈ 49050.84
4. Since we can only have whole containers:
Number of complete smaller containers = 49050
Therefore, approximately 49050 smaller cylindrical containers can be completely filled using the oil from the larger tank.

80% of 700 is:

A. 560
B. 570
C. 580
D. 590
Correct answer is: A. 560
80% of 700 is calculated as 560.

Simplify the equation 5 + 2 × 6 ÷ 3 (2)=?

A. 9
B. 13
C. 7
D. 5
Correct answer is: C. 7
By using PEMDAS: Parentheses: Simplify inside the parentheses first. There is nothing to simplify inside the parentheses themselves, but we should identify that

3(2) means

3×2.

3(2)=3×2=6

So the equation becomes:

5+2×6÷6

Multiplication and Division: Next, we perform multiplication and division from left to right.

First, perform the multiplication:

2×6=12

Then, perform the division:

12÷6=2

Now the equation is:

5+2

Addition: Finally, perform the addition:

5+2=7

So, the simplified value of the equation is:

5+2×6÷3(2)=7

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