PREMIUM
📚 FPSC SST 2026 Preparation Group
Join Our WhatsApp Group for SST Past Papers & Mock Tests
✅ Daily MCQs • 💡 Expert Tips • 📚 Past Paper Discussion
Join Group →

If the sequence is 2·1² + 4·2² + 6·3² + … + 20·10², find its value.

A. 5060
B. 6050
C. 4080
D. 3050
Correct Answer: B. 6050

Correct answer: 6050. The nth term is 2n × n² = 2n³, so the sum is 2(1³ + 2³ + … + 10³) = 2 × 55² = 2 × 3025 = 6050.

Background: Each term has the form (2n) × n² = 2n³, so the series is 2(1³ + 2³ + … + 10³).

  • 5060: 5060 does not match the computed sum.
  • 4080: 4080 does not match the computed sum.
  • 3050: 3050 does not match the computed sum.

Did you know? The sum of the first n cubes equals the square of the sum of the first n numbers: [n(n + 1) ÷ 2]².

Memory trick: Sum of cubes = (sum of numbers)², then multiply by 2.

Is this answer helpful and correct?

0 agree0 disagree

Leave a Comment

Your email address will not be published. Required fields are marked *

Join Our WhatsApp Channel ×
Scroll to Top