Computer Science MCQS

Computer Science MCQ with detailed explanations for students & freshers preparing for entrance exams, various tests, interviews, competitive exams like GATE exam, interview, competitive examination and entrance exam.

The _ presents a uniform device-access interface to the I/O subsystem, much as system calls provide a standard interface between the application and the operating system.

A. a) Device drivers
B. b) I/O systems
C. c) Devices
D. d) Buses
Correct answer is: A. a) Device drivers
Device drivers present a uniform device-access interface to the I/O subsystem.

They act as a bridge between the operating system and hardware devices, providing a standardized way for applications to interact with different types of devices. This abstraction layer simplifies the development of applications and makes the I/O subsystem more manageable.

The operating system maintains a __ table that keeps track of how many frames have been allocated, how many are there, and how many are available.

A. a) memory
B. b) mapping
C. c) page
D. d) frame
Correct answer is: D. d) frame
frame table is a data structure used by the operating system to keep track of physical memory frames. It contains information about the status of each frame, such as whether it's free or allocated to a process, and if allocated, which page is currently stored in it. This information is crucial for memory management and page replacement algorithms.

Using transient code, _ the size of the operating system during program execution.

A. a) maintains
B. b) changes
C. c) increases
D. d) decreases
Correct answer is: B. b) changes
b) changes

Transient code is temporary code that is loaded into memory only when needed and then removed. As a result, the size of the operating system changes during program execution. It increases when the transient code is loaded and decreases when it is removed.

The operating system and the other processes are protected from being modified by an already running process because __

A. a) every address generated by the CPU is being checked against the relocation and limit registers
B. b) they have a protection algorithm
C. c) they are in different memory spaces
D. d) they are in different logical addresses
Correct answer is: A. a) every address generated by the CPU is being checked against the relocation and limit registers
every address generated by the CPU is being checked against the relocation and limit registers

This is the correct answer.

Relocation register: Holds the base address of a process's memory space.

Limit register: Specifies the maximum size of a process's memory space.

Whenever a process generates an address, the CPU checks it against these registers. If the address is within the process's allowed memory range, it's valid. Otherwise, it's considered an invalid access and is prevented. This mechanism protects the operating system and other processes from being corrupted by a rogue process.

This protection is essential for maintaining system integrity and security.

The operating system is responsible for?

A. a) bad-block recoveryb) booting from diskc) disk initializationd) all of the mentioned
B. all of the mentioned
C. The operating system is responsible for:
D.
Correct answer is: B. all of the mentioned

The main memory accommodates __

A. a) cpu
B. b) user processes
C. c) operating system
D. d) all of the mentioned
Correct answer is: C. c) operating system
c) operating system

The main memory primarily accommodates the operating system. It stores the core components of the OS, which are essential for managing the computer's resources and controlling its operations. While user processes and parts of the CPU (registers, cache) also reside in memory, the operating system is the primary occupant and manager of main memory.

Swapping _ be done when a process has pending I/O, or has to execute I/O operations only into operating system buffers.

A. a) must never
B. b) maybe
C. c) can
D. d) must
Correct answer is: A. a) must never
a) must never

Swapping a process with pending I/O or one that is executing I/O operations into operating system buffers is not advisable because:

Inconsistency: If a process is swapped out while waiting for I/O, the I/O completion might occur while the process is not in memory. This can lead to data inconsistency.

Overhead: Continuously swapping processes in and out due to I/O operations can introduce significant overhead, impacting system performance.

To avoid these issues, operating systems typically employ techniques like buffering or double buffering to handle I/O operations without requiring process swapping.

A deadlock avoidance algorithm dynamically examines the __ to ensure that a circular wait condition can never exist.

A. a) operating system
B. b) resources
C. c) system storage state
D. d) resource allocation state
Correct answer is: D. d) resource allocation state
This means it looks at the current allocation of resources to processes and the maximum resource needs of each process to determine if granting a resource request would lead to a deadlock. By analyzing this information, the algorithm can prevent deadlock by denying requests that could potentially create a circular wait.

The Banker's Algorithm is a classic example of a deadlock avoidance algorithm.

 For an effective operating system, when to check for deadlock?

A. a) every time a resource request is made at fixed time intervals
B. b) at fixed time intervals
C. c) every time a resource request is made
D. d) none of the mentioned
Correct answer is: A. a) every time a resource request is made at fixed time intervals
Checking for deadlock every time a resource request is made is the most effective approach.

This is because:

Early detection: It allows for immediate identification of potential deadlocks, preventing them from escalating.

Resource optimization: By detecting deadlocks early, the system can take corrective actions, such as process termination or resource preemption, to avoid system-wide issues.

Efficient resource utilization: Continuously monitoring resource requests helps in optimizing resource allocation and preventing deadlocks.

While checking at fixed intervals might be less computationally expensive, it increases the risk of missing deadlock conditions, especially if the interval is too long.

Therefore, checking for deadlock at every resource request offers the best balance between efficiency and deadlock prevention.

The FCFS algorithm is particularly troublesome for __

A. a) operating systems
B. b) multiprocessor systems
C. c) time sharing systems
D. d) multiprogramming systems
Correct answer is: C. c) time sharing systems
FCFS (First Come First Served) is particularly troublesome for time-sharing systems.

In time-sharing systems, multiple users share the CPU, and each user expects a quick response. FCFS, where processes are executed in the order they arrive, can lead to long wait times for users whose processes are behind long-running ones. This results in poor responsiveness and user dissatisfaction.

To address this, time-sharing systems typically use scheduling algorithms like Round Robin or Priority scheduling, which provide better fairness and responsiveness.

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